Tell me the pdf of bigger one in two pigs, if we assume the pdf of each pig's weight is all Gaussian pdf with same mean (m) and variance (s^2). The weight value of bigger one is denoted by
[EQ-1] w >= w1 >= w2, where w1 and w2 are the weights of two pigs, respectively. Base on the assumption, we have [EQ-2] E[w1] = E[w2] = m, [EQ-3] E[(w1-m)^2] = E[(w2-m)^2] = s^2, then, I guess, the mean and variance of w become [EQ-4] m(w) = m + s/Sqrt(Pi), [EQ-5] s(w)^2 = (-1+Pi)*s^2/Pi, while we are considering only the case s > 0, m > 0. Does it suppose to be going to correct way? BR, -- James K. ([EMAIL PROTECTED], http://myhome.naver.com/txdiversity) - Any remarks, proposal and/or indicator to text would be greatly respected. - Private opinions: These are not the opinions from my affiliation. . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
