Bill Jefferys <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>... > In article <[EMAIL PROTECTED]>, > [EMAIL PROTECTED] (Eddie Jaye) wrote: > > Hi Bill
thank you for your response. You say that as the questions stands that it cannot be solved or calculated using the fisrt 3 lines of explanation. prehaps i should have made myself clearer. what i mean to say what is the probability of A given the evidence of B and C and D which are all conditional probalities and dependent on A but which ARE NOT mutually exclusive and independent on each other. Thus as i mentioned before a student can belong to a series of stastics that are grouped together in terms of age, gender, ethnicity and so on. if the solution to this problem is already in some form provided by you as given below P(A|B&C&D)=P(B|A&C&D)P(C|A&D)P(A|D)/[P(B|C&D)P(C|D)], i do apologise and then ask if you could tell me where i can find the other mathetical formulas you hinted about. and politely ask for a brief explaination as to why it cannot be solved soley using the input sources given. thanks Eddie . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
