Hi all,

I've been trying to understand the breakdown point of M-Estimators in
linear regression however there are a couple of issues that continue
to confuse me.  I would be grateful if any of you could clarify these
issues or point me to a reference that may help me.

Lets begin with the quadratic estimator - it has a breakdown point of
zero because a single outlier (erroneous response/output variable) or
leverage point (erroneous explanatory/input/factor space variable) can
skew the estimate by an arbitrary amount.  The root cause of this skew
is the large residual caused by the outlier/leverage point.

Now, redescending M-Estimators are designed to limit the effect of
large residuals.  If a residual is over a certain magnitude it is down
weighted.  Because the residuals of both outliers and leverage points
are down weighted in the same way, you would think that M-Estimators
would be resistant to both types of error.  But the literature says
that this isn't the case.  M-Estimators are said to have a zero
breakdown point of zero because a single outlier can cause an
arbitrarily large skew in the estimate.  But why?  Any residual over
the cutoff point will have small effect on the summation.  What is the
breakdown point of an M-Estimator if only outliers are considered? 
Can 50% contamination be tolerated?

Why are leverage points considered to have a stronger skewing effect
than outliers?  Is it because in a linear model (e.g. y=mx+c), the
explanatory variable x (i.e. the leverage point) is multiplied by the
parameter m?  If this is the case, then I return to my previous
argument, the leverage point may have a larger residual due to the
multiplication, but the redescending M-Estimator should limit the
effect of this residual.

In the literature that I have read, it is often said that M-Estimators
have a breakdown point of 1/(p+1) where p is the number of parameters.
 Is this result correct, or is it limited to the GM-Estimators that
are supposed to limit the effect of leverage points by weighting
residuals.

You help is much appreciated.
Julian
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