Let me rephrase: Suppose I give a frequency and intensity for a poisson variable, such as temperature. For days over 100 degrees, lambda = 1 (i.e., we get on average one such day per time period). For days over 120 degrees, lambda = .25 (we get on average one such day per four time periods).
In other words, lambda for temp > 100 is 1.0 lambda for temp > 120 is .25 Does this mean that lambda for temps between 100 and 120 is .75? That is, on average we get .75 days falling in the 100 to 120 temperature range? Richard Ulrich <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>... > On 11 May 2004 11:47:30 -0700, [EMAIL PROTECTED] (rishi) wrote: > > > Let X follow a poisson distribution. > > > > Suppose for some phenomenon, lambda = 1 for X > 100. > > Lambda =1 for X greater than 100.... what is X? > > > Suppose further that lambda = .3 for X > 300. > > > This is an extra explanation? .3 for greater than 300? > We should re-interpret the first statement? > > > Is it true that lambda = .7 for 300 > X > 100 ?? > > You already said that lambda=1 for X greater than 100. > I think you have some logical or notational problem. > (Again, what is X?) . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
