"Richard Ulrich" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> On Sun, 25 Apr 2004 09:48:28 +0100, "Rod" <[EMAIL PROTECTED]>
> wrote:
>
> > Strictly speaking it is still non-linear because the errors are centred
on x
> > not e^-x. Probably won't make a big difference though
> >
>
> Aren't the errors centered in Y?
>
> Isn't X  assumed to be measured without error?
> (so, e^-x  is equally without error.)

Fair point.
Would still want to convince myself that these errors could all come from
the same normal distribution.
If Y is getting big (say instead, we were looking at e^(x)) this may not be
true as error is often proportional to Y.

>
> -- 
> Rich Ulrich, [EMAIL PROTECTED]
> http://www.pitt.edu/~wpilib/index.html


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