Hi Gael, Thank a lot for the confirmation.
Best, Hung On Thu, Jul 30, 2020 at 10:31 AM Gael Guennebaud <gael.guenneb...@gmail.com> wrote: > Hi, > > yes, with "x = x.array().log()" the operation is done inplace, no > temporary. > > Gaël > > On Wed, Jul 29, 2020 at 12:22 AM Hung Dang <hungp...@gmail.com> wrote: > >> Hi, >> >> I need to compute x = log(x) in-place, with x can be either a vector or a >> matrix. This task can be done using either a simple for-loop or x = >> x.array().log(). The second solution is vectorized, however, I am not sure >> if it can be done in-place. Is there any better solution? >> >> Regards, >> Hung >> >> >> >> >> >> >> >>
