Hey Brian, Thanks for taking the time to respond. I looked at the post you suggested and I don't think that would give me what I need. I believe that what you're suggesting would provide me with the most views of a single url by a unique visitor. In other words, if a url has 1004 entries, where one person viewed it a thousand times and 4 people each viewed it once, the crazy person who kept refreshing would be at the top of the facet response. I need to know that the url had 5 unique visitors. If there was only one url in the index this would work in a roundabout way, because I could look at the total number of terms returned in the facet. Unfortunately, that's just not the case here.
Of course, if I'm misunderstanding what your post suggests, or if I've missed something, please let me know! Thanks, Matt On Friday, January 10, 2014 5:54:46 PM UTC-5, InquiringMind wrote: > > Matthew, > > I don't know if this is simple (though it was easy enough for me in Java), > or even if it's exactly what you had in mind. But it sounds as if you are > asking for a hierarchical combination to include the top URLs by uid. Is > that correct? > > If so, perhaps > this<https://groups.google.com/d/msg/elasticsearch/_oMbAnpjSGg/II4Tzf6RoSwJ>will > give you some ideas. > > Hope this helps! Good luck! > > Brian > -- You received this message because you are subscribed to the Google Groups "elasticsearch" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/elasticsearch/3e7ef115-1b27-4e67-b6dd-185b84f9c76d%40googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
