I do not have a power meter so I figured that I could compute power from a peak to peak measurement using my scope. This should be accurate enough for ballpark knowledge. However, the measured voltage increases as frequency increases with the 10 meter voltage being nearly double the 80 meter voltage. This would mean power increases with frequency unless the formula I was going to use is missing a frequency dependent component.
I have a KAT2 installed and I used a good 50 ohm resistive load. My math follows: Vrms = Vp-p/(2*sqrt(2)) Vrms = Irms*R assuming purely resistive load or Irms = Vrms / R if Prms = Irms*Vrms substituting yields Prms = (Vp-p * Vp-p) / (8 * R) I know that Pave = Prms / 2 but that does not help much because I would still get more than 10 Watts out on 10 meters when set for 5 watts out. Where did I go wrong? Fran _______________________________________________ Elecraft mailing list Post to: [email protected] You must be a subscriber to post to the list. Subscriber Info (Addr. Change, sub, unsub etc.): http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/subscribers.htm Elecraft web page: http://www.elecraft.com
