Bruce, Look in the DL1 instruction manual - there is a graph of power vs. output voltage properly compensated for the diode curve.
The first page of the DL1 manual provides the formula of P=((Vx1.414) +0.15)^2/50 -- for those with sharp eyes, there is an extra right paren in th eequation in the manual. Simplifying the formula to V^2/25 will work at higher power levels where the diode drop becomes insignificant (about 2 watts and above). 73, Don W3FPR > -----Original Message----- > > I was doing a calibration of a KAT2 I just built and had a significant > error to adjust for Forward power (displayed power was ~30% of > measured). When I looked closely at the DL1 I noticed the trace to the > detector comes from the center of the 50 ohm load. That means the > detected voltage is across 1/2 the load (25 ohms) and changes the power > calc to V^2/25 = P vs. of V^2/50 = P. Can someone confirm this? > > Thanks... > > Bruce Bowman NM5B > Sasnta Fe, NM > > -- No virus found in this outgoing message. Checked by AVG Anti-Virus. Version: 7.0.308 / Virus Database: 266.11.10 - Release Date: 5/13/2005 _______________________________________________ Elecraft mailing list Post to: [email protected] You must be a subscriber to post to the list. Subscriber Info (Addr. Change, sub, unsub etc.): http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/subscribers.htm Elecraft web page: http://www.elecraft.com
