OK, I get the 1.414 term now. The RF is sampled at the voltage divider, and the diode/capacitor circuit rests at the peak voltage it sees - which is half what the transmitter is delivering. To get peak voltage of the RF waveform at the input to the DL1, we multiply by two. To get the RMS we then divide by 1.414. But 2/1.414 is 1.414, so we simply multiply the voltage by 1.414.
Now for the 0.15 term....? Chip ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[email protected] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html
