Actually it's "I-squared R drop", and a 1/2 reduction in current results in a 75% loss reduction. Monty K2DLJ
On Aug 6, 2012, at 1:27 PM, Bob <[email protected]> wrote: > Electric meters measure current consumption on both 120v legs when > calculating total watt hour consumption. So it matters not one bit if the > loads are balanced or unbalanced from a billing point of view. Rumors to > the contrary are simply not correct. > > The reason for running the amplifier at a higher voltage is that it will > reduce the IR voltage drop. Because the operating voltage has doubled, the > required current has been cut in half. Therefore the IR drop (loss in the > wiring) has been cut in half. > > 73, Bob, WB4SON > ______________________________________________________________ > Elecraft mailing list > Home: http://mailman.qth.net/mailman/listinfo/elecraft > Help: http://mailman.qth.net/mmfaq.htm > Post: mailto:[email protected] > > This list hosted by: http://www.qsl.net > Please help support this email list: http://www.qsl.net/donate.html ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[email protected] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html
