What is most amazing about this thread is that two sides can state the exact
same thing, but find fault with and argue with the other.. (???)
It's bordering on comical.
73, Charlie k3ICH
----- Original Message -----
From: "Walter Underwood" <wun...@wunderwood.org>
To: "Richard Fjeld" <rpfj...@embarqmail.com>
Cc: "Elecraft Reflector" <elecraft@mailman.qth.net>
Sent: Monday, October 07, 2013 12:26 PM
Subject: Re: [Elecraft] K3 Suddenly died
Of course. My point was "for a given current", so 20A at 120V and 20A at
13.8V. --wunder, K6WRU
On Oct 7, 2013, at 9:03 AM, Richard Fjeld wrote:
I stated the voltage drop across a resistance (the wire conductor) is
directly proportional to the amount of current flow (amperage) through
it.
For a given resistance, as the current increases through it, the voltage
drop increases in it.
Changing the supply voltage will change the current flow through the
same conductor resistance and affect the voltage drop in it.
-----Original Message----- From: Walter Underwood
Sent: Monday, October 07, 2013 10:20 AM
To: Elecraft Reflector
Subject: Re: [Elecraft] K3 Suddenly died
There is a point which could be made -- the percentage voltage drop is
bigger at 12V than at 120V.
If the voltage drop on your power supply wire is 2V for a given current,
that is the same regardless of the supply voltage. With a 120V supply,
the wire will deliver 118V and with 13.8V it will deliver 11.8V.
So the same voltage drop can matter more at lower supply voltages.
Note that I'm ignoring the difference between AC and DC and skin effect.
wunder
K6WRU
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