In a recent message, Alan <[email protected]> writes
So you would expect it to read 3 dB lower (half the power), which is half an S unit.
This is something that has always puzzled me, Alan. I agree that -3dB is half the power (in watts), but S-meter calibration is related to (micro)voltage. It is often assumed that doubling ones power increases the signal at the receiving end by one S-point. But what is the technical explanation of this?
73 David G4DMP -- + - - - - - - - - - - - - - - - - + | David M Pratt, Kippax, Leeds. | | Website: http://www.g4dmp.co.uk | + - - - - - - - - - - - - - - - - + ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[email protected] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [email protected]
