Since I don't know what precedes the word "thus" in the quotation below I
would ask if someone could explain this phenomenon for me.
I am trying to visualize this with a thought experiment. In an earlier post
someone (Skip?) mentioned that early transmission lines were sometimes hollow
copper tubes, to respect the fact that AC flows only on the outside of a
conductor. So, imagine a hollow tube carrying RF (which may approximate the
fast rise and fall times of a high voltage strike). Current is flowing all
over the surface, I gather. Now squeeze the tube along its length so that a
cross section becomes an ever flatter ellipse. At the last instant squeeze it
so that the sides are in contact with each other. What happens to the current
flow as that squeezing occurs? Is it still all around the squished tube until
the instant the two sides join? And then it all flows primarily along the
edges of the now flat conductor? Howcome?
Tnx,
Ted, KN1CBR
------------------------------
Message: 3
Date: Wed, 25 Apr 2018 18:45:39 -0700
From: Wes Stewart <[email protected]>
To: [email protected]
Subject: Re: [Elecraft] OT: Grounding Question
Message-ID: <[email protected]>
Content-Type: text/plain; charset=utf-8; format=flowed
Radio Engineering and Radio Engineer's Handbook are two different
critters.? My
copy of Radio Engineering is the third edition and the pertinent
information is
on p.20.
To partially quote: "Thus, with a flat-strip conductor, the current flows
primarily along the edges."
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