Thanks everyone. I thought it was right, but until now, the value
listed in the table matched exactly what was printed on the component.
It has been soldered nicely into place. I'm just about finished the
filter board! I think, I sure hope I don't mess up the toroidal
inductors.
73
Joe
NE3R
On 5/4/07, Mike Morrow <[EMAIL PROTECTED]> wrote:
>...The table shows C17 & C19 as 56, but the components I
>have are labeled 560J. Do I have the right capacitors
There's a very good summary of capacitor marking conventions at:
http://xtronics.com/kits/ccode.htm
There's some interesting non-obvious conventions to this marking system. Most
know that a capacitor marked ABC is equal to AB x 10^C pF. So yours are 56 x
10^0 = 56 pF. Similarly, 562 would be 56 x 10^2 = 5600 pF.
So what would 569 be? Not 56 x 10^9 or 56000000000 pF, as you might think, but
actually 56 x 0.1 = 5.6 pF. When the third digit is 9 the multiplier is 0.1.
When the third digit is 8, the multiplier is 0.01. You'd be surprised how few
know that.
The J on your caps is the code for the value tolerance in percent. All this is
explained on the web site cited above.
73,
Mike / KK5f
(Sorry this topic isn't about the K3...not!)
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