Would this method work? Put the K2 into test mode (see manual page 100) and measure the key down TX input power (disables PA).
Your maximum allowed input power is 10W plus the figure measured. Regards, Paul M1PAF. -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of David Woolley Sent: 31 October 2007 22:37 To: List Elecraft Subject: [Elecraft] [K2] DC Input (was:N2CQ QRP Contest Calendar: Nov 2007) Ken Newman wrote: > HA-QRP Contest (CW - 80 Meters) *** QRP Contest*** > Nov 1, 0000z to Nov 7, 2400z > Rules: http://www.radiovilag.hu/haqrp2.htm The rules for this specify a limit of 10 watts DC input. Is there any sensible way of calculating a, non-zero, absolute lower bound for the power consumed by the K2 driver and exciter, so as to be able to honestly say that the PA DC input is less than 10 watts without limiting the total current to 750 to 800 mA to make the whole transceiver transmit mode DC input be under 10 watts. Assume a K2 with the standard output transformer windings. -- David Woolley Emails are not formal business letters, whatever businesses may want. RFC1855 says there should be an address here, but, in a world of spam, that is no longer good advice, as archive address hiding may not work. _______________________________________________ Elecraft mailing list Post to: [email protected] You must be a subscriber to post to the list. Subscriber Info (Addr. Change, sub, unsub etc.): http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/subscribers.htm Elecraft web page: http://www.elecraft.com _______________________________________________ Elecraft mailing list Post to: [email protected] You must be a subscriber to post to the list. Subscriber Info (Addr. Change, sub, unsub etc.): http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/subscribers.htm Elecraft web page: http://www.elecraft.com
