Forest suggests: For each pair of candidates X and Y, let F(X,Y) be the number of ballots on which X is ranked equal first with Y, plus the number of ballots on which X is ranked ahead of Y. Similarly, let L(X,Y) be the number of ballots on which X is equal last with Y (i.e. on which neither is ranked ahead of any other candidate), plus the number of ballots on which X is ranked behind Y. How are ballots that list one of or neither of X and Y counted?
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