On Behalf Of Paul Kislanko
Yes, I noticed I didn't add right and got the pairwise percentages wrong... Blame it on trying to do too many things at once but wanting to get a point in. Probabilistically, A should not have twice the chance of winning as B and C in the example. The actual probabilities that would be "fair" would all be nearer 67:66:66. ---- Election-methods mailing list - see http://electorama.com/em for list info
