Forest was the first to mention the Better-Than-Expectation strategy for Approval--the strategy whereby a voter votes for the candidates who are better than his/her expectation for the election, better than the value of the election. So the voter using that strategy votes for a candidate if that candidate is so good that s/he would rather have that candidate in office than hold the election.


One can come up with situations in which that isn�t optimal. But it maximizes one�s utility expectation if certain approximations or assumptions are made. One usual assumption is that there are so many voters that one�s own ballot won�t change the probabilities significantly. By one approach, it�s also necessary to assume that the voters are so numerous that ties & near-ties will have only 2 members, and that Weber�s Pij = Wi*Wj, the product of the win-probabilities of i & j.

But, instead of the last 2 assumptions named in the previous paragraph, it would also be enough to assume that when your vote for a candidate increases his win-probability, it decreases everyone else�s win-probability by a uniform factor.

That�s the approach that Russ used, except that he didn�t state that assumption.

Russ, don�t take any of this as criticism--I�m just telling you so that you�ll know.
In your derivation-description, you stated the goal "to keep the sum of all probabilities at unity without changing the probability ratios." But keeping the other candidates win-probabilities in the same ratios isn�t a goal of the derivation; it�s an assumption by which Better-Than-Expectation maximizes the voter�s utility expectation. It�s important to state assumptions, and that particular assumption is really key to the derivation.


You said that delta Pj the increase in candidate j�s win-probability if the voter votes for j. But later you say that actually that increase is different from delta Pj. Preceding a quantiy by delta usually indicates a change in that quantity. You started out that way, but then, in your derivation, delta Pj no longer represented that change.

One could let delta Pj really always stand for the increase in j�s win-probability. That makes for a more direct derivation:

Let E = your expectation in the election if you don�t vote for j.

Let Pj = candidate j�s probability of winning if you don�t vote for j.

Let delta Pj = the amount by which j�s win-probability increases if you vote for j.

Let Uj be j�s utility for that you.

So, if the you vote for j, j�s win-probability will be Pj + delta Pj.

So, if the you vote for j, then j�s contribution to the expectation is (Pj + delta Pj)Uj.

When the you vote for j, what�s the combined contribution of the other candidates to the expectation? Well, first, what�s their contribution if you don�t vote for j? It�s E minus j�s contribution if you don�t vote for j. That�s E - PjUj.

Now you want their combined contribution to the expectation when you make their wins less probable by voting for j. Aside from the fact that it turns out to accomplish our goal, it�s a reasonable simplifying assumption to assume that we reduce their win probabilities by a uniform factor.

Then, the combined contribution of the non-j candidates to your expectation is it�s initial value,
E - PjUj, mulitplied by the factor by which you reduce their win probabilities.


If you don�t vote for j, the probability that a non-j candidate will win is 1 - Pj.

If you vote for j, the probability that a non-j candidate will win is 1 - Pj - delta Pj. That�s one minus j�s new probability of winning.

So, multiply the initial non-j candidates� expectation contribution, E - PjUj, by the ratio of the probabilities in he previous 2 paragraphs:

(E - PjUj) * ( (1 - Pj - delta Pj)/(1 - Pj)) That�s the j candidates�new contribution to your expectation.

So, add j�s new contribution to the expectation and that of the non-j candidates:

(Pj + delta Pj)Uj + (E - PjUj)(1 - Pj - delta Pj)/(1 - Pj)

We want the new expectation to be more than the initial expectation:

E < (Pj + delta Pj)Uj + (E - PjUj)(1 - Pj - delta Pj)/(1 - Pj)

Solve that for Uj. You get:

Uj > E

Because of the directness of that derivation, it doesn�t need summations to be written, and that makes it acceptable to people who wouldn�t want to look at something with summation notation.

Also, because delta Pj continues to mean the increase in Pj, this derivation is straightforward and direct.

_________________________________________________________________
Is your PC infected? Get a FREE online computer virus scan from McAfee� Security. http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963


----
Election-methods mailing list - see http://electorama.com/em for list info

Reply via email to