I wrote (in my last posting): > Here is a particular example... >My ratings and utilities for the three candidates... A>B>C (100, 5, 0) >Probability of each candidate winning if I vote A>B>C... A: 40%, B: 55% C: >5%. >Probability of each candidate winning if I vote A>C>B... A: 45%, B: 40% C: >20% >Total probabilistic utility given A>B>C vote = (100*.4) + (5*.55) + (0) = >42.7 >Total probabilistic utility given A>C>B vote = (100*.45) + (5*.4) + (0) = >47
Sorry that the second set of probabilities don't add up to 100%. It's not really important, but anyway here's a revision. My rankings and ratings: A>B>C (100, 5, 0) Probabilities given A>B>C: A: 40%, B: 55%, C: 5% Probabilities given A>C>B: A: 45%, B: 35%, C: 20% Probabilistic utility for A>B>C: (100*.4) + (5*.55) = 42.75 Probabilistic utility for A>C>B: (100*.45) + (5*.35) = 46.75 James ---- Election-methods mailing list - see http://electorama.com/em for list info
