RE: First minus last tiebreaker

[DEMOREP1]

The first minus last tiebreaker applied to the standard simple 3 choice
circular tie--

N1  A > B > C
N2  B > C > A
N3  C > A > B

The tiebreaker-

A  N1 - N2 + N3
B  N2 - N3 + N1
C  N3 - N1 + N2

Note- this is also a modification of the Bucklin method which only sums the
votes in the early places to get a majority.