Dear Blake,
you wrote (23 Apr 2001):
> The question was asked of Mike, but I'll respond anyway. He must
> be refering to an example like this:
>
> A>B 40
> B>C 39
> C>A 38
> A ties with D
> D>B 5
> D>C 4
In this example, D is the unique Schwartz winner. Ranked Pairs is
indecisive between A and D.
Is it also possible to create an example where Ranked Pairs chooses
decisively a candidate outside the Schwartz set (so that it is clear
that whether Ranked Pairs chooses outside the Schwartz set doesn't
depend on the used tiebreaker)?
Markus Schulze
