Some more about the mysteries of clones --- 34 ABC 33 BCA 32 CAB
99 First 2 places A 66 B 67 Max C 65 X a 100 percent clone of A comes along 34 AXBC 33 BCAX 32 CAXB 99 First 2 places Last 2 places A 66 33 X 34 65 B 33 66 Max C 65 34 Thus, should head to head math be done at least down to a 3 choices level to remove clones in a single winner case ??? Of course, it is a matter of degree regarding clones --- a 100 percent clone versus a 99 percent clone versus a 98 percent clone etc. Also, of course, if another choice is added, then an existing choice may become a 100 percent clone --- as if X in the above goes before A in all votes. As usual, I note that there are YES or NO *absolute* votes in addition to any *relative* votes.
