Stephane Rouillon wrote: > > B>D and D>C; 14-8 each > > A>C and C>B; 13-9 each ...and A>D; 13-9 > > B>A; 12-10. > >I do obtain the same results than you but not the same last conclusion: > >Ranked pair: B>A>D>C >it overturns C>B (13-9) > >SSD: A>D>C>B >it overturns B>A (12-10) ...but BD (14-8) too! >Correct me if I am wrong. >It is not fair to only count overturns related to the winner...
I don't see why I need to consider B>D to be overturned... A is already the Condorcet winner if we ignore B>A. But if I ignore A and search for the new Condorcet winner with SSD, I'll overturn C>B just like ranked pairs does (not B>D). After all, there's no difference between RP and SSD in the three candidate case. I'm honestly unsure if the final ranking of the candidates other than the winners, and the defeats that need to be overturned to produce such a ranking, are at all relevant. It seems like this is more of a multi-winner issue. -Adam ---- For more information about this list (subscribe, unsubscribe, FAQ, etc), please see http://www.eskimo.com/~robla/em
