A ballot might look like Shade One Grade per Candidate as well as (optional) Plus or Minus Signs:John Brown A B C D E F G H J K L M N P Q R S T U V W X Y Z + - Josie Rose A B C D E F G H J K L M N P Q R S T U V W X Y Z + -
but I have some remarks.[etc.]
First why remove I and O if the ballots is presented like that?
I do not think there can be confusion...
Next, I doubt we really need + and - signs because there is rarelly
26 candidates or more, but in case it is a solution.
Finally do you have any idea how to let the voter put Demorep's (yes/no)
limit so to use residual approval weights?
A voter could draw a big vertical bar? With informatics it would work...
For 9 candidates, it could look like:
Shade at Most One Grade per Candidate
And Indicate your Limit (|) Between Acceptable and Undesirable Candidates:
Amy Jones A
B C D
E F G
H I
Barbara Smith A B
C D E
F G H
I
Charles Jones A
B C D
E F G
H I
Daniel Smith A
B C D
E F G
H I
Eve Jones
A B C
D E F
G H I
Fibbie Smith A
B C D
E F G
H I
Georges Jones A
B C D
E F G
H I
Harry Smith A
B C D
E F G
H I
Isabel Jones
A B C
D E F
G H I
An example of completed ballot:
Shade at Most One Grade per Candidate
And Indicate your Limit (|) Between Acceptable and Undesirable Candidates:
|
Amy Jones A
B C D
# | F G
H I
Barbara Smith A B
C D E |
F G #
I
Charles Jones #
B C D
E | F G
H I
Daniel Smith A
B C D
E | F G
H I
Eve Jones
A # C
D E | F
G H I
Fibbie Smith A
B # D
E | F G
H I
Georges Jones A
B C D
E | F G
H I
Harry Smith A
# C D
E | F G
H I
Isabel Jones
A B C
D E | #
G H I
|
that we would translate as:
Charles(yes) > Eve(yes) = Harry(yes) > Fibbie(yes) > Amy(yes) > Isabel(no)
> Barbara(no) > Daniel(no) ? Georges(no)
I know some would prefer to put unranked Candidates as neutral but
how could we attribute them a (yes/no) index?
It does not bother me because I treat the no indicator
not as a negative vote. Using negative votes is like giving someone
the opportunity to deny someone else any representation.
In other words a 45 - 23 result is very different and shall not
have the same consequences as a 25 - 3 result. It produces
the same outcome for single-winner contests, but it should not
for fair (proportional) multiple winners methods.
Steph.
