Abd,
You wrote:

>Note that if the method allows equal ranking, adding clones does not 
>require additional ranks.
>
How on earth do you work that out?  "Require" for what purpose?

You seem to be assuming that it doesn't matter which member of a set of 
clones wins, which is odd
because it is perfectly possible that the two rival front-runners are 
members of  the same set of clones.


Chris Benham






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