Warren has done a lot of research into Range voting. I wonder how well
RV works as a Condorcet completion method.
Actually, I was on his site the other day
(http://www.rangevoting.org/MedianVrange.html), looking at the
Balinski-Laraki median range voting method. It made me wonder what the
results would be if you took the combined score (or the average) of all
range votes above the median for every candidate. It looks like it
should satisfy the majority criterion, assuming people have a single top
preference (ties at the top score would complicate that a bit).
I was at work, though, so I didn't play with the numbers, though if
someone has done that, it would be interesting to see. It probably is on
the range voting site, though I didn't see it.
Michael Rouse
Paul Kislanko wrote:
I personally like the idea of using Bucklin to break a Condorcet cycle.
Suppose alternatives Ax, Ay, and Az prevent there being a Condorcet winner.
Then find the best ranks Rx, Ry, Rz for which a majority of the voters rank
Ax, Ay, Az AT LEAST Rx,y,z respectively. If one of Rx, Ry, Rz is better than
the others, that determines the winner. If Rx=Ry=Rz (or the two best are
equal) then use the size of the respective majority (i.e. if 100 voters and
52 give Rx but 51 give Ry then Ax wins the tie with Ay.)
If both the R and #votes providing the majority that determines R are the
same we have a true tie. Either flip a coin or have a runoff.
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Terry
Bouricius
Sent: Thursday, May 14, 2009 2:48 PM
To: Warren Smith; election-methods
Subject: Re: [EM] Cramster question
Warren,
However, using first-choice plurality to settle Condorcet cycles could
easily elect the Condorcet-loser (the candidate who loses in every
pairwise match-up). There are many far superior cycle breakers. I
personally favor ranked-pairs because it is both reasonable, and
relatively easy to explain to lay people (unlike many cycle breakers).
Terry Bouricius
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