Er... --- En date de : Mer 27.7.11, Kevin Venzke <[email protected]> a écrit : > So the first one asks: > 50% rated 3? 33.3% rated a 2+? 16.7% rated a 1+? > four-slot ballot to mean 133.3%. So then I get: > 66.7% rated 3? 50% rated 2? 33.3% rated 1+? > > I must not have this correct, because isn't the first test > strictly > harder than the second? What is an example where you win on > the first > method but not the second?
What I was thinking when I asked this was that if you got 33.3%+ 2+ ratings, you also necessarily got 33.3% 1+ ratings. So, if I understand things, the way to not win on the second method is if somebody else has fewer 2+ ratings than you but more 1+ ratings than you. So the combined method is something like identifying the ambiguity between two Bucklin-like levels and having a pairwise contest to resolve it. Honestly I don't how well that is going to work... It seems to me it's the better bet to try to avoid having the pairwise contest. Kevin Venzke ---- Election-Methods mailing list - see http://electorama.com/em for list info
