I've just realized that "disregard cyclical defeats" i(where a cyclical defeat is a defeat that's in a cycle) isn't enough to define the Schwartz set. But (looking at this for the first time) I don't know if it would be enough to gain MMC and Clone-Independence.
Anyway, Symmetrical-IC-Schwartz-Top would say: Determine the Schwartz-set, by the Symmetrical IC definition of "beat", and elect the Schwartz-set's most top-ranked member (To rank a candidate at top is to not rank anyone over hir). [end of Or maybe the following slightly different method would be ok (it would have to have a different name): "Beats" is defined by Symmetrical IC. Disregard any defeat that's in a cycle. If exactly one candidate is unbeaten, s/he wins. If all or no candidates are unbeaten, then elect the most top-ranked candidate. If some, but not all, candidates are unbeaten, then elect the most top-ranked unbeaten candidate. [end of definition of un-named alternative method] Mike Ossipoff ---- Election-Methods mailing list - see http://electorama.com/em for list info
