Here's the way I would explain the CMJ tiebreaker in your example: "This candidate's median is a C, and to get up to the median vote uses 43.1% of those C votes."
What this means: This candidate would be beaten by a candidate with a median of A or B or a candidate with a median of C where the median used up more than 43.1% of the C votes. This candidate would beat any candidate with a median of D and any candidate with a median of C where the median used up less than 43.1% of the C votes. How it is calculated: There are 578,536 voters, with half of that being 289,268. The bottom half of the votes, then, are the 19,663 F votes, plus the 81,286 E votes, plus the 121,121 D votes, plus 67,198 of the 155,781 C votes. 67198/155781 is 0.431. ~ Andy On Wed, Jan 2, 2013 at 7:55 AM, Fred Gohlke <[email protected]> wrote: > Good Morning, Jameson > > re: "Each voter grades each candidate from A to F. Voters may > give as many or as few of each grade as they want. Then > each candidate's grades are put in order and the similar > grades are evenly spread out. For instance, grades of B > (3.0) are evenly spread over a continuum between B+ (3.5) > and B- (2.5)." > > It is not clear how or why grades should be adjusted. If a voter gives a > candidate a grade of B, what is the justification for changing it to B+ or > B-? More to the point, what is the benefit? If a candidate gets: > > Grade Voters > A 26,781 > B 173,904 > C 155,781 > D 121,121 > E 81,286 > F 19,663 > > can not the candidate's grade be calculated without adjusting the value of > any of the voters' wishes? > > Fred > ---- > Election-Methods mailing list - see http://electorama.com/em for list info >
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