That pattern should be rewritten to:
Path.expand("some_file.ex", __DIR__)
or:
Path.join(__DIR__, "some_file.ex")
I don't believe we should introduce Path.relative_to_current_file because
it would have to be a macro in order to retrieve the current file and
__DIR__ is readable enough.
*José Valim*
www.plataformatec.com.br
Skype: jv.ptec
Founder and Director of R&D
On Fri, May 12, 2017 at 3:02 PM, Sam Davies <[email protected]> wrote:
> I've seen this pattern a lot:
>
> `Path.expand('./some_file.ex', Path.dirname(__ENV__.file))`
>
> which returns the path relative to the location of the file it is
> specified in.
>
> I wonder if we can package this up in a convenient helper method,
> something like:
>
> `Path.relative_to_file('./some_file.ex')` or
> `Path.relative_to_current_file('./some_file.ex')`
>
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