function_exported?/3 returns false if the module is not loaded (i.e. it
does not load the module). Code.ensure_loaded?/1 should be preferred but it
is a very expensive operation to be allowed in guard.

The is_atom check is the way to go.



*José Valimwww.plataformatec.com.br
<http://www.plataformatec.com.br/>Founder and Director of R&D*

On Mon, Oct 16, 2017 at 9:34 PM, Allen Madsen <[email protected]>
wrote:

> This is the best way I know how to determine if it's a module vs an atom.
>
> function_exported?(X, :__info__, 1)
>
> You won't be able to use it in a guard though.
>
> Allen Madsen
> http://www.allenmadsen.com
>
> On Mon, Oct 16, 2017 at 3:10 PM, Martin Svalin <[email protected]>
> wrote:
>
>> The closest thing we have is `Code.ensure_loaded/1`. If you don't check
>> that the module exists, you're basically just checking that the input is an
>> atom. And if you use ensure_loaded, you'll have a predicate function with
>> side effects. You'd also break the expectation of guard safety with the
>> `is_` prefix.
>>
>> Would your `is_module/1` have different behaviour than `is_atom/1`? Would
>> it be true only of atoms of the form `:"Elixir.SomeModule"`? I'm not sure
>> it should, since `defmodule :random_atom` is valid.
>>
>> Which is a long way of saying, I think you should use `is_atom`. Perhaps
>> with a line comment `# for modules`.
>>
>>
>> mån 16 okt. 2017 kl 20:02 skrev Devon Estes <[email protected]>:
>>
>>> We just encountered something that seemed kind of odd, so I wanted to
>>> pass it by the list to see if it could be a possible feature.
>>>
>>> In Benchee we want to accept either a module or a function as an
>>> argument to a function. We'll have different behavior depending on the type
>>> there (since we're expecting any module passed in to implement a certain
>>> behaviour). However, there's no check for `is_module`. We were thinking of
>>> using `is_atom` (see here: https://github.com/PragTob/ben
>>> chee/pull/148/files#diff-e8ef07ff6be58cfaaaf6f03420fc53e7R75), but that
>>> seems sort of confusing to me. I know technically modules are atoms, but
>>> would it be possible to have an `is_module` function that can be used in
>>> guard clauses and elsewhere that would more accurately convey the sort of
>>> thing we're trying to do?
>>>
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