For 8 fields or less I can do import Json.Decode as Decode exposing ((:=))
collectionDecoder : Decode.Decoder (List Test) collectionDecoder = Decode.list (Decode.object8 Test ("id" := Decode.int) ... ) How to decode JSON object with more than 8 fields? -- You received this message because you are subscribed to the Google Groups "Elm Discuss" group. To unsubscribe from this group and stop receiving emails from it, send an email to elm-discuss+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.