Hi Uwe,
Try:
#+ATTR_LaTeX: :float nil
#+CAPTION: La función La función $x^2 e^{-\alpha x} = \frac{1}{\alpha}$,
$\alpha=-\ln(1-p)$ con $p=0.01$ con $p=0.3$
[[./images/dfp_03.png]]
Best regards,
Juan Manuel
Uwe Brauer writes:
> Hi
>
> Currently
>
> #+CAPTION: La función La función $x^2 e^{-\alpha x} = \frac{1}{\alpha}$,
> $\alpha=-\ln(1-p)$ con $p=0.01$ con $p=0.3$
> #+NAME: fig:plotcalor23
>
> [[./images/dfp_03.png]]
>
> Gets translated to
>
> \begin{figure}[htbp]
> \centering
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \caption{\label{fig:plotcalor23}La función La función \(x^2 e^{-\alpha x}
> = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\) con \(p=0.01\) con \(p=0.3\)}
> \end{figure}
>
> For reasons that needs a longer explanation I would need.
>
>
>
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \captionof{figure}{\label{fig:plotcalor23}La función La función \(x^2
> e^{-\alpha x} = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\) con \(p=0.01\) con
> \(p=0.3\)}
>
>
> How can this be achieved?
>
> Thanks
>
> Uwe Brauer
>
>
>
>
