If I have a plain-list element that looks something like (plain-list (:type unordered :begin 260 :end 571 :contents-begin 260 :contents-end 571 :structure ((260 2 "- " nil nil nil 338) (338 2 "- " nil nil nil 413) (413 2 "- " nil nil nil 489) (489 2 "- " nil nil nil 571)) :post-blank 0 :post-affiliated 260 :parent nil))
I seem to be able to get the items from the list using org-element-property :structure (per the documentation), giving me: ((260 2 "- " nil nil nil 338) (338 2 "- " nil nil nil 413) (413 2 "- " nil nil nil 489) (489 2 "- " nil nil nil 571)) and then the first list item using `car`, as I expected: (260 2 "- " nil nil nil 338) But if I try to use org-element-property on that, of course it fails because it's not an element, as I understand it, rather it's an object(?). So how do I get the the beginning and end? I can obviously just do: (car list-item) ; head (car (last list-item)) ; tail but I'm wondering if there's a better way. ---- Explanation: What I'm trying to do overall is to get the various details out of a list item that might look like: - State "DONE" from "NEXT" [2023-06-05 Mon 10:54] \\ example So I'd like to be able to get the date of the timestamp (this isn't an absolute requirement, I'm happy enough to just using the current date), and the "example" text (which, obviously, isn't always "example"). If I have to use buffer-substring-no-properties and my car & car (above) then I will, but it would be nice to know there's an easier/better/more appropriate way of getting at what I want. Thanks in advance.