On 4/13/06, Barry Warsaw <[EMAIL PROTECTED]> wrote: > On Thu, 2006-04-13 at 12:47 -0500, Lukasz Szybalski wrote: > > > I am sending an email with smtplib, and i need to get a copy of what i > > have sent out. > > Is there a way to do it? > > > > I am storing the information into a database so I need to get message > > id, time etc from the message that gets sent out. > > Do you want the mail server to send you a copy, or do you want a copy of > what you send to the mail server? If the former, just add a BCC header > and include the return address you want the copy sent to. If the > latter, just do str(msg) to get the text.
Although that works to get what i created i also need to get : Date: Thu, 13 Apr 2006 11:11:17 -0700 (PDT) Message-Id: <[EMAIL PROTECTED]> Anyway to do it? Does smtplib have a way to return exact thing it is sending? > -Barry > > > > -----BEGIN PGP SIGNATURE----- > Version: GnuPG v1.4.2.2 (GNU/Linux) > > iQCVAwUARD6RY3EjvBPtnXfVAQIoFwP9HEayxK92vSYnsv4U9REibulopyFVS/PP > s4NYOkSZdiFhzJvLa5ikLndtWsBlW+7WQcBHjAJQM/Lro15A0OPwwTz/GlMuyRBZ > w3+oJYvA0usfXkyzf599mzWJeDMIVQEn5XI71bCr2A+4d81OdbbZR+B4dc2TyHxE > kokXiQsLVMY= > =UKfv > -----END PGP SIGNATURE----- > > > -- Lukasz Szybalski www.lucasmanual.com _______________________________________________ Email-SIG mailing list [email protected] Your options: http://mail.python.org/mailman/options/email-sig/archive%40mail-archive.com
