Another comment,
this is an analytical problem the steps are, first use image theory to get
rid of the plane and end up with two parallel cylinders of radius r at a
distance 2D from each other. then using image theory again the wires can be
reduced to line charges then the problem is easily solved
C= (pi)(epsilon)/ Ln[(D/r)+sqrt{(D/r)^2-1}]
if D/r is bigger than 1 then since Ln[x+sqrt(x^2-1)]=cosh^(-1) x for x>1
C=(pi)(epsilon)/cosh^(-1)(D/r)
Vicente RodrÃguez, Ph.D., E.I.T.
RF/Electromagnetics Engineer
ETS-Lindgren
(an ESCO Company)
P.O.Box 80589, Austin TX 78708-0589
phone 512.835.4684 x648
fax 512.835.4729
[email protected]
http://www.emctest.com
http://home.austintx.com/~vicenter
> -----Original Message-----
> From: William D'Orazio [SMTP:[email protected]]
> Sent: Friday, December 15, 2000 3:07 PM
> To: EMC Posting (E-mail)
> Subject: Capacitance calculation
>
>
> Gents,
>
> I do not have all my resources next to me and I was wondering what
> is the capacitance between a cylinder of radius R separated from a plane.
> The distance between the center of the cylinder and the plane is D (see
> Fig.1).
> In addition is the dielectric constant of styrofoam 1.
>
> Thanks in advance,
>
>
>
> <<...>>
>
> Fig. 1
>
>
>
>
> <<...>>
>
> William D'Orazio
> CAE Electronics Ltd.
> Electrical System Designer
>
> Phone: (514) 341-2000 (X4555)
> Fax: (514)340-5552
> Email: [email protected]
>
>
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