Hi Alan,

Your confusion over 3 and 6dB is understandable.

Sometimes "sound intensity" and "sound pressure" are improperly used
interchangeably.  Intensity is proportional to the square of pressure.  If
the intensity is doubled, one would say that there is a 3dB increase in
sound intensity; 10*log(2I/I).  However, if the pressure is doubled there is
a 6dB increase in sound pressure; 10*log(2p/p)^2.

Also, when doubling (or halving) the DISTANCE between source and receiver,
one would subtract (or add) 6dB when dealing with a point source.  However,
for a cylindrical source there is a 3dB difference when doubling/halving
distances.

Good luck,
Paul Hare



From: [email protected]
[mailto:[email protected]]On Behalf Of Hudson, Alan
Sent: Thursday, January 23, 2003 4:15 AM
To: EMC-pstc (E-mail)
Subject: RE: Acoustic noise calculations for multiple shelves



John Woodgate wrote:
> The noises are uncorrelated (largely), so you add 3 dB, not 6.

Now I'm confused! I always thought it was noise *level* (similar to voltage
level) not noise *power*, and hence it was 20*log(ratio) not 10*log(ratio).
So I've been using 6dB for doubling noise, not 3dB.

I'll need to consult some basic texts, methinks.

Regards,

Alan
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