You're partially correct, Ken.  However, the photon (in
quantum mechanics) is the particle that mediates the
electromagnetic force; photon also the name given to the
particle that is a quantum of electromagnetic energy.  Thus,
photons are involved as the particle analog to an
electromagnetic wave.  Also, an electron beam is not
identical to an electromagnetic wave in the sense you are
trying to characterize them.

The primary difference between bosons (photons are bosons)
and fermions (which leptons are classified as; electrons are
leptons) is boson have integer spins, while fermions have
fractional spins (spin is a classification of "intrinsic
angular momentum") and bosons are not constrained by the
Pauli Exclusion Principle, whereas fermions are.

This does not address why an electromagnetic wave of longer
wavelength may be redirected by the presence of an external
magnetic or electric field, while light is less affected.

More properly, it is not an electron that creates an
electromagnetic wave, it's charge; electrons just happen to
possess a quantum of electric charge.  An electric charge at
rest radiates an electric field.  An electric charge in
motion creates a magnetic field, irrespective of
acceleration.

Theoretically, it should be possible to magnetically or
electrically redirect light.

By definition, light is visible and exists only between the
wavelengths of 700 nm-400 nm.  "Light" and "optical
radiation" has been extended to other wavelengths (ir and
uv) in the common vernacular mostly because of "lasers"
being used at those wavelengths.



Regards,

Peter L. Tarver, PE
Product Safety Manager
Sanmina-SCI Homologation Services
[email protected]


> From: Ken Javor
> Sent: Friday, January 10, 2003 9:24 AM
>
> The answer is independent of frequency, it is the
> nature of the particle
> (electron vs. photon) that is key.  I have
> forgotten the terminology, but
> one type  of particle is called a boson, and per
> my (quite possibly faulty)
> recollection, bosons do not interact with
> electromagnetic fields.  For
> example, you can use either an electric or
> magnetic field to deflect and
> point an electron beam, but you cannot do so with
> a beam of light.
>



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