Sorry, the second line was missed from my earlier reply. I don't know about voltage, but in maths it is the hypotenuse of a right-angled triangle! I therefore presume it is the measured voltage calculated from knowing the active and reactive components of the voltage. Regards, Neil Helsby
Original Message dated 18/12/2003, 15:50:17 Author: "Brian O'Connell" <[email protected]> Re: : Good People What is the basis of this formula for working voltage ? sqroot(a^2 + b^2) thanks, Brian ********************************************************************** This email and any files transmitted with it are confidential and intended solely for the use of the individual or entity to whom they are addressed. If you have received this email in error please notify the system manager. This footnote confirms that this email message has been swept for the presence of computer viruses and is believed to be clean. ********************************************************************** This message is from the IEEE EMC Society Product Safety Technical Committee emc-pstc discussion list. Visit our web site at: http://www.ieee-pses.org/ To cancel your subscription, send mail to: [email protected] with the single line: unsubscribe emc-pstc For help, send mail to the list administrators: Ron Pickard: [email protected] Dave Heald: [email protected] For policy questions, send mail to: Richard Nute: [email protected] Jim Bacher: [email protected] All emc-pstc postings are archived and searchable on the web at: http://www.ieeecommunities.org/emc-pstc
