Dear John,
 
Thank you so much for teaching me.
 
I will keep your suggestion (fix a training session with Agilent) on my wish
list.  I did browse Agilent's training courses yesterday.  Due to the current
ecomonic downturn, it is not easy to obtain an approval for an out of state
training.  Instead, online resources become handy.  Agilent has online video
demo (such as http://wireless.agilent.com/networkanalyzers/enademo.htm).  I
started viewing the "Network Analyzer Basics" demo and had to finish it later
on.  To perform measurement, I have my experienced RF design colleague (who's
office is 50 feet from mine) show me the first time.  I ask him questions when
I feel something is not right.
 
Best regards,
Grace

 
On 2/9/09, John Woodgate <[email protected]> wrote: 

        In message 
<[email protected]>,
dated Mon, 9 Feb 2009, Grace Lin <[email protected]> writes:
        
        

                I have learned from members that ANSI C63.4 and CISPR 16-1-2 
are the
calibration standards for LISN for my daily measurement.  I have one of my two
LISNs ship out last week to an accredited calibration lab.  I wonder if I need
to ship out the other one for calibration since the second one is used for
support equipment. 
                


        I would strongly advise it. I have found strange differences in results 
with
two apparently good LISNs. This may be why the CISPR 16-1-2 requirements have
been made more detailed over the past few years.
        
        

                Is it sufficient that I verify it in-house?  If yes, I would 
need your help
with calibration.
                


        It's always worth knowing how to do it.
        

                 
                I study A.8 of CISPR 16-1-2 Edition 1.2 and Annex E of ANSI 
C63.4-2003 this
morning.  Here are my questions:
                 
                1. The title of A.8 is "Measurement of the voltage division 
factor of an
artificial mains V-network".  What does "voltage division factor"?  Does it
mean insertion loss?
                


        Not exactly; it's the ratio of input voltage, at the connector supplying
mains power to the EUT to output voltage at the connector for the measuring
receiver. Differences in the impedances at these points are not taken into
account, so the ratio is not 'insertion loss' as normally defined.
        
        A.8 was written by someone who knew the subject very well, so well that 
it
can be very difficult for others to understand. And the requirement for
voltage division factor is 'hidden' in the caption of Figure 4.10.
        
        

                2. Is the adapter, mentioned in Figure A.6a, Figure A.6b of 
CISPR 16-1-2 and
Figure E.1(a) of ANSI C63.4, commercially available? 
                


        I don't know: I've made mine myself.
        
        

                If not, is there any guidelines to make it (type of connectors, 
size and
length of wires/cables, etc.)? 
                


        I think there is no need to be extremely meticulous about this. Whatever
mains connector you use, it is not matched to 50 ohms or anything else, but it
is electrically 'short' (compared with a wavelength) even at 30 MHz, so it has
little effect. Just keep all connections short and rigid (movement of
connections can impair repeatability).
        
        

                Should I take a pin from a power plug and solder one end to a 
SMA
receptacle? 
                


        No. The connections in Figure A6a are **coaxial cables**, so that isn't 
a
single connection to L1 but a coaxial connection to L1 and ground.
        
        

                If yes, is there any preference for the type of the receptacle 
(cable jack,
panel jack, bulkhead, etc. http://www.a
phenolrf.com/Products/CatalogPages/sma_catalog.pdf)?
                


        Just keep the wires short and rigid, if the connection is not coax. I 
have,
for example, mounted two BNC connectors (L1/ground and N/ground) directly on a
metal plate attached to the cover of a UK 13 A plug.  I also have a single BNC
connected by a short (100 mm)50 ohm coax to a 13 A plug. Inside the plug is a
network of five 82 ohm resistors. One goes from each power pin to the ground
pin. The other three are connected as a delta, one apex to each power pin, and
the third to the incoming coax inner. The outer of the coax goes to ground, of
course. This gives an input impedance close to 50 ohms, and 30 ohms between
power pins and from each power pin to ground (network alone; no generator
connected). The insertion loss is 11.2 dB. I don't remember whether someone
told me about this arrangement or whether I invented it. With this device, you
can look at both outputs of the LISN at once, if the switching allows you
access to both outputs simultaneously (as, in my opinion, it should) for
direct comparison purposes.
        
        

                3. How do I terminate the mains port?  The LISN, Solar 
9252-50-R-24-N (same
as 9252-50-R-24-BNC except with N connector) comes with a permanent attached
power cord.  Should I pick up a receptable (no wire attached) and connect 50
ohms resistor to L and N respectively, and connect the other end of the
resistors to ground reference?
                


        That's all you can do without modifying the LISN. You could cut the 
cable
short, fit an in-line IEC 320 free socket to it and use an IEC 320 mains lead
in future. Then you would have a terminator consisting of an IEC 320 plug with
two parallel pairs of 100 ohm resistors inside, power pins to ground.
        
        

                4.  Is there any requirement (VSWR etc.) for the 50 ohms 
terminator?
                


        Any commercial terminator is most unlikely to have a poor VSWR up to 30 
MHz.
Even a 51 ohm metal film resistor inside a BNC plug is likely to be OK.
        
        

                5.  Is 10 dB pads needed?  Figure A.6a and Figure A.6b of CISPR 
16-1-2 show
them.  The NOTE from Figure E.1(b) states "Attenuator pads not used with
network analyzer.
                


        The pads are there to prevent errors due to mismatched impedances. Your
set-up and LISN may or may not need them. You can only tell by measuring with
and without to see if the results differ.
        
        

                6.  Figure A.6a and Figure A.6b of CISPR 16-1-2 show two ports 
of network
analyzer are used.  Figure E.1(b) shows three ports of network analyzer are
used.  The vector network analyzer I have access to comes with four ports
(http://www.home.agilent.com/agilent/product.jspx?cc=US&lc=eng&pageMode=
                OV&pid=810708&ct=PRODUCT&id=810708).  The calibration kit 
available is 3.5mm
(http://www.home.agilent.com/agilent/product.jspx?cc=US&lc=eng&pageMode=
                
OV&pid=1000003542%3Aepsg%3Apro&ct=PRODUCT&id=1000003542%3Aepsg%3Apro).  How
many ports do I need to connect to (port 1&2, or port 1&2&3)? 
                


        You only need to use one output port and one input port.
        
        

                I start using a VNA two weeks ago and is not familiar with it.  
As a matter
of fact, I used a demo VNA (only two ports
http://www.us.anritsu.com/products/37000D-Series_Lightning-Family-of-mic
                roW-VNAs--Value-Line_ARSPG_ARQQSidZ643.aspx) to calibrate cable 
loss.
                


        I suggest you try to fix a training session with Agilent.
        -- 
        OOO - Own Opinions Only. Try www.jmwa.demon.co.uk
<http://www.jmwa.demon.co.uk/>  and www.isce.org.uk <http://www.isce.org.uk/> 
        Things can always get better. But that's not the only option.
        John Woodgate, J M Woodgate and Associates, Rayleigh, Essex UK
        
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