In message <OFA00408F8.C2AAF2B2-ON88257983.00655457-88257983.0065C93E@US.Schneider-E lectric.com>, dated Thu, 12 Jan 2012, [email protected] writes:

As I understand it, of this battery chemistry is charged/discharged correctly, there shouldn't be a problem, but how do they wear out?

The fire problem doesn't seem to be related to 'wear-out' - the inference is that a manufacturing defect is involved, and that is possibly the existence of voids in the construction, where layers that should be in close contact are not.

These voids create areas of higher thermal resistance, and if the temperature rises enough to melt solid electrode or electrolyte materials, they may well turn from partial insulators to extremely good (ionic) conductors.

I recall such an effect with wirewound resistors having a glass-fibre core. Once a hot-spot developed and the glass melted, the resistance dropped to near zero, with dazzling light effects and emission of magic smoke.
--
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