Note that vertical waves invert in polarity on reflection with the
ground plane, where horizontal polarized waves do not.

I remember that calculations were much easier when the send antenna is
seen as if it were under the ground plane for the reflected wave

and above for the direct wave.

Also note that conclusions drawn (and they are spectacular) about the
functioning of the OATS are correct but applicable

to a infinitely small radiate/receive antenna only. For larger antenna
one might need to integrate over the size of both the antennas.

 

Gert Gremmen

 

Van: Pawson, James [mailto:[email protected]] 
Verzonden: vrijdag 31 juli 2015 16:59
Aan: [email protected]
Onderwerp: [PSES] Calculating Reflection Angles on OATS/SAC

 

Hi,

 

I'm trying to calculate the distances/angles at which a maximum (in
phase) or minimum (anti-phase) signal would occur on an OATS/SAC.

 

I can do this simply when the TX and RX antennae are the same height
above the reflecting surface as the point of reflection lies halfway
between the two antennae, Distance_tx = Distance_rx. The direct and
reflected paths can be calculated using simple geometry and the
wavelength is given by lambda = c / f.

 

However when the height of the RX antenna is different to the height of
the TX antenna then the horizontal distance to the reflection point is
no longer equidistant. I can see that the ratio Height_tx / Distance_tx
= Height_rx / Distance_rx remains the same because the angle of
reflection is the same. But I'm left with two unknown Distance terms in
the equation.

 

Is there a standard equation for calculating the reflection angle on an
OATS/SAC with a varying height antenna? Or can someone give me some
pointers to help me figure it out myself? I was so distracted thinking
about this that I missed my turnoff whilst cycling home the other day.

 

I've tried Googling but maybe I'm not putting in the right search term.

 

Any assistance gratefully received.

Thanks and regards,

James

 

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