Microvolts/m requires 20*log( ), like anything based on voltage or
current. Your example of a transmitter is based on power.
On 2024-01-23 16:24, Larry K. Stillings wrote:
Hello All,
Maybe this is not the correct forum and I should put in an inquiry
into the ANSI C63.10 committee directly, however before I did that I
wanted to get some help here.
In the 2020 edition of the ANSI 63.10 standard they have added a
calculation example page for pulsed emissions in Clause 7.6.3.
In a nutshell the example shows a duty cycle of ~36% (25 mS on time /
70 mS off time). The readings are taken in dBuV/m peak values and then
a duty cycle correction of 20 * log (on time / total time) is applied
or -8.9 dB to determine the average value of the emission.
Here is where it falls apart for me. If you are taking measurements in
dBuV/m wouldn’t the duty cycle correction factor be determined with 10
* log (on time / total time). Let’s take an example of a transmitter
being on 10 % of the time, isn’t that a 10 dB reduction? If the device
is on 1% of the time isn’t that a 20 dB reduction?
Or for some reason because it is a pulsed emission you are allowed to
use 20 * log and have a 20 dB reduction for a 10% duty cycle or less
because anything greater than 20 dB is the maximum allowable
correction / reduction for a pulsed emission?
Larry K. Stillings
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Keep trying
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