Thanks for the replies, and Hi Doug! Agreed, I can't think of an MOV worth 
buying that would survive a 1200-1400V dielectric test.  We might install 
jumpers to bypass the MOVs, and megger the completed boards. Note I did find a 
copy of UL 60335-1 (3rd edition) and section 16.2 has current requirements.  
All below 1mA, except for  3.5 mA for "STATIONARY CLASS I MOTOR-OPERATED 
APPLIANCES."   which still sounds low.  There's a section stating that Class 1 
Heating appliances tripping current is 0.75 mA per kW of rating, which is more 
in the ballpark.  Still very much a WIP. happy weekend all, Colorado Brian 

---------- Forwarded Message ----------
From: Douglas Powell <[email protected]>
To: [email protected]
Subject: Re: [PSES] Dielectric test, electric appliances
Date: Fri, 13 Mar 2026 16:04:48 -0600


Richard, I believe the MOV, or any type of protection, may offer some level of 
surge protection; however, factors such as lead length will limit its 
effectiveness, particularly concerning other parts of the mains connection 
within the larger building. The primary goal is to have the surge protection as 
close as possible to the equipment it is meant to protect. In larger 
facilities, the line impedances and other parasitics will significantly 
influence the protection results. From a standards perspective, quantifying 
these factors is extremely challenging. ~Doug Douglas E PowellFounder & 
Principal ConsultantVertex Compliance Consulting (VertexCC)Laporte, Colorado, 
USALinkedIn Colorado Registered Business | Entity ID: 20191778678(UTC-06:00, 
US-MDT) 
  
On Fri, Mar 13, 2026 at 2:44&#8239;PM Richard Nute <[email protected]> 
wrote:Hi Derek:
 
 I guess I am wrong about the MOV subjected to the hi-pot test.  Thanks for 
correcting me.  
 
 However&hellip; the MOV is there to protect the equipment from overvoltage.  
Doesn&rsquo;t it protect all equipment that is connected to that branch circuit 
and ALL of the 120-volt premises system?  I think we only think of the 
immediate load.  The MOV must protect ALL of the distributed circuit, not just 
the load.
 
 True?
 
 Thanks, and best regards,
 Rich
 
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