Don't forget to take into account the efficiency of a leadscrew, which I believe averages around 35%. In other words, 35% of the rotational torque available gets transformed to linear force.
Stephen Wille Padnos wrote: > > The leadscrew diameter isn't important for the force calculation. > > The motor can output 200 ounces force at a one inch radius, as you > said. For one revolution, the 200 ounces of force is applied over 2*pi > inches of travel, but produces 0.2 inches of table motion. Just divide: > 200 * (2*pi*r) / (0.2) = force in ounces > =2000*pi, or about 6280 ounces force (close enough to 400 pounds). > > The units are ounces * (inches) / (inches), which is ounces since the > lengths cancel out. > > - Steve > > ------------------------------------------------------------------------- This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/ _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users
