The template parameters for 'function' only seem to accept method pointers
for the given type, not for a parent type, so this kinda borks up even
though it feels like it *ought* to work to just pass in &Base::doSomething
here.
(It might be worth filing as an issue on github so it doesn't get
forgotten; seems like something that would come up at API boundaries.)
Try using a static_cast on the method pointer, from the base to the derived
type:
EMSCRIPTEN_BINDINGS(bindo) {
emscripten::class_<Derived>("Derived")
.constructor()
.function("doSomething",
static_cast<void(Derived::*)()>(&Base::doSomething));
}
It's a little verbose, but seems to do the right thing and doesn't require
writing extra functions.
-- brion
On Thu, Dec 10, 2015 at 1:31 AM, Joshua Auerbach <[email protected]>
wrote:
> Let's say I have the following in C++
>
> class Base {
> public:
> void doSomething() {
> //do something here
> }
> };
>
> class Derived : public Base {
> };
>
> And I want to expose Derived to js including the inherited method
> doSomething (a toy example illustrative of a bigger issue)
>
> Is this possible without also exposing Base? Or do I really need to
> recreate the entire class hierarchy in my bindings?
>
> I know these bindings work:
>
> emscripten::class_<Base>("Base")
> .function("doSomething", &Base::doSomething);
>
> emscripten::class_<Derived, emscripten::base<Base>>("Derived")
> .constructor();
>
> But this does not:
>
> emscripten::class_<Derived>("Derived")
> .constructor()
> .function("doSomething", &Derived::doSomething)
>
> unless I change the C++ definition of Derived to
>
> class Derived : public Base {
> public:
> void doSomething() { Base::doSomething(); }
> };
>
> I never want Base to be exposed to js just the inherited method. Is there
> any way to expose those without recreating the hierarchy or making trivial
> overrides like I do above?
>
> Thanks!!!
> Josh
>
> --
> Dr. Joshua E. Auerbach
> Postdoctoral Researcher
> Laboratory of Intelligent Systems
> École Polytechnique Fédérale de Lausanne
>
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