You should just use /scap see http://www.osgi.org/javadoc/r4v42/org/osgi/service/http/HttpService.html#registerServlet (java.lang.String, javax.servlet.Servlet, java.util.Dictionary, org.osgi.service.http.HttpContext)
HTH
-Simon
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|"fox" <f...@protelsws.com>
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|"Equinox development mailing list" <equinox-dev@eclipse.org>
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| Date: |
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|12/08/2009 09:33 PM
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|Re: [equinox-dev] Re: How can I register a servlet to receive andhandle the
path like "/*"? |
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|equinox-dev-boun...@eclipse.org
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Hi Gunnar:
Thanks for your help,
but then I found another problem: if I want the servlet to handle the
request with the path "/scap/*",I try to modify the alias to "/xcap/", it
throws "java.lang.IllegalArgumentException: Invalid alias '/xcap/' ",how
should I resolve this problem?
Thanks so many.
2009-12-09
fox
发件人： Gunnar Wagenknecht
发送时间： 2009-12-08 20:31:53
收件人： equinox-dev
抄送：
主题： [equinox-dev] Re: How can I register a servlet to receive andhandle
the path like "/*"?
Am 08.12.2009 09:08, schrieb fox:
> When I convert a httpservlet to a bundle,I found that the first param of
> Httpservice.registerServlet method does not support the path define
> like "/*",but I want to achieve this functionality ,what should I do?
Just '/' instead of '/*'. The OSGi HttpService applies a prefix matching.
-Gunnar
--
Gunnar Wagenknecht
gun...@wagenknecht.org
http://wagenknecht.org/
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