And what if you add hydrogen at this point (of catalyzation) and at chamber
pressure and temperature? Would the hydroxyl (OH) groups combine with the extra
hydrogen exothermicly, that is OH + OH + H2 = 2 H20? Or still produce H2O + O2
first and then the extra hydrogen and oxygen  produce another water molecule
exothermicaly? Two steps instead of one.
    If the two hydroxyl (OH) groups combine do they go straight to H2O + O2 or do
the spare O's combine later in an endothermic way? Adding hydrogen to the peroxide
catalyzation would  not really be a biprop, but a kind of catalyst extender. The
exhaust would be just water as steam.

Pierce Nichols wrote:

>
>
>          Actually, the reaction process is going to start by breaking
> peroxide into two OH groups, which will then recombine later into H2O and O2.
>
> >--

>>>>>>>>>>>>>>>>----<<<<<<<<<<<<<<<<<
........ Alex Fraser  N3DER .........
......... [EMAIL PROTECTED] .......
[~]_>^</\-[~]_>^</\-[~]_>^</\-[~]_>^<


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