Ash Berlin wrote: >> >> I don't think ||= and ??= are very difficult to define clearly. >> Perhaps just a line each in terms of the expanded syntax. I don't >> think they would add much bloat to engines. Perhaps just better to add >> them both and move on to discussing classes, lambdas, or processes. > > a ||= b; > a = a || b;
Note that in general, 'a op= b' is *not* equivalent to 'a = a op b', the main issue being that 'a op= b' evaluates 'a' once, and 'a = a op b' evaluates it twice. It is difficult, perhaps impossible, to give a correct expansion of the compound assignment operators in terms of the corresponding non-assigning operator, because there isn't (AFAIK) any way to preserve an evaluated LeftHandSideExpression, without applying GetValue to it, while the right-hand-side is being evaluated. So these operators have to be treated as primitive. -- David-Sarah Hopwood ⚥ _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
